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In professional baseball, the pitching distance of 6060 feet 66 inches is the distance from the front of the pitcher's plate (or rubber) to the rear of the home plate. (a)(a) Assuming that a 95mi/h95 \mathrm{mi} / \mathrm{h} fastball travels that full distance horizontally, what is its flight time, which is the time a batter must judge if the ball is "hittable" and then swing the bat? (b)(b) Research indicates that even an elite batter cannot track the ball for the full flight and yet many players have described seeing the ball-bat collision. One explanation is that the eyes track the ball in the early part of the flight and then undergo a predictive saccade in which they jump to an anticipated point later in the flight. A saccade suppresses vision for 20 ms20 \mathrm{~ms}. How far in feet does the fastball travel during that interval of no vision?

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Givens

  • l=60 ft 6 inl=60\ \text{ft}\ 6\ \text{in} - the pitching distance
  • v0=95 mihv_0=95\ \frac{\text{mi}}{\text{h}} - the initial speed of the ball
  • Δt=20 ms\Delta t=20\ \text{ms} - the duration of the saccade

Required

  • a) τ\tau - the time it takes for the ball to travel the distance ll
  • b) Δx\Delta x - the distance the ball travels during Δt\Delta t

How can we use the fact that there are no forces acting along the horizontal axis?

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