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In the following equation, which describes the fission of uranium, what do i, ii, and iii represent? i+235Uraniumii+91Krypton+iii\mathrm{i}+^{235} \mathrm{Uranium} \rightarrow \mathrm{ii}+^{91} \mathrm{Krypton}+\mathrm{iii} (a) 1 neutron, 142Boron^{142} \mathrm{Boron}, heat energy, (b) 1 neutron, 142Barium^{142} \mathrm{Barium}, 135Cesium^{135} \mathrm{Cesium}, (c) 1 neutron, 142Barium^{142} \mathrm{Barium}, kinetic energy, (d) Kinetic energy, 142Boron^{142} \mathrm{Boron}, potential energy, (e) Potential energy, 142Barium^{142} \mathrm{Barium}, kinetic energy.

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c) 1 neutron, 142^{142}Barium , kinetic energy

Fission is a radioactive decay process in which a nucleus of an atom divides into two or more fragments, resulting in the release of a large amount of energy. It occurs when neutron slams into a large atomic nucleus, forcing it to split into smaller parts. During splitting, new neutrons are released, which can encourage extra fission reactions, leading to a nuclear fission chain reaction that produces an enormous amount of energy.

i + 235^{235}Uranium \rightarrow ii + 91^{91}Krypton + iii

1 neutron + 235^{235}Uranium \rightarrow 142^{142}Barium + 91^{91}Krypton + kinetic energy (3 neutrons in motion)

i = 1 neutron

ii = 142^{142}Barium

iii = kinetic energy

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