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Question

In the following exercise, find the value(s) of k that makes the function continuous over the given interval.

f(x)={x2+3x+2x+2,x2k,x=2f(x)=\left\{\begin{aligned} \frac{x^{2}+3 x+2}{x+2}, & x \neq-2 \\ k, & x=-2 \end{aligned}\right.

Solution

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The function is already continous for x2x\neq -2, since it is equal to a continous rational function x2+3x+2x+2\frac{x^2+3x+2}{x+2} on that interval. Now we only have to make f(x)f(x) continous at 2-2.

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