## Related questions with answers

Question

In the following exercise, identify which expressions are equivalent to the given expression.

$\frac{1}{2} x+3+\frac{1}{2} x$

a. $\frac{1}{2}(x+3)$

b. $x+3$

c. $3 x+3-x$

Solution

VerifiedStep 1

1 of 4$\underline{TRY\ x= 2}$

${\color{#4257b2} \dfrac{1}{2}x+3+\dfrac{1}{2}x } = \dfrac{1}{2}(2)+3+\dfrac{1}{2}(2) =1+3+1=4+1={\color{#c34632}5}$

$a)\ {\color{#4257b2} \dfrac{1}{2}\left(x+3 \right) } = \dfrac{1}{2}\left((1)+3 \right)= \dfrac{1}{2}\left(1+3 \right)=\dfrac{1}{2}\left(4 \right) ={\color{#c34632}2}$

$b)\ {\color{#4257b2} x+3 } = (2)+3=2+3={\color{#c34632}5}$

$c)\ {\color{#4257b2} 3x+3-x } = 3(2)+3-(2)=6+3-2=9-2 ={\color{#c34632}7}$

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