Question

In the following problem, determine an approximate value of the solution at t=0.4 and t=0.5 using the specified method. For starting, values use the values given by the RungeKutta method. Compare the results of the various methods with each other and with the actual solution (if available).

Use the fourth order Adams-Moulton method with h=0.1.

y=y2+2ty3+t2,y(0)=0.5y^{\prime}=\frac{y^2+2 t y}{3+t^2}, \quad y(0)=0.5

Solution

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Answered 4 months ago
Answered 4 months ago
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The Adams-Moulton method formula is

yn+1=yn+h24(9fn+1+19fn5fn1+fn2)\begin{align*}y_{n+1}=y_n+\dfrac{h}{24}(9f_{n+1}+19f_{n}-5f_{n-1}+f_{n-2})\end{align*}

Where fn=yn2+2tnyn3+tn2f_{n}=\dfrac{y_n^2+2t_ny_n}{3+t_n^2}.

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