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Question

In the previous problem, the vector in the x-direction is 4 units long. Vectors i\vec{i} and j\vec{j} are unit vectors in the x- and y-directions, respectively. A unit vector is a vector that is 1 unit long. So the x-component of p\vec{p} is the vector 4i4 \vec{i}, a product of a scalar and a vector. A scalar is a quantity that has only magnitude, not direction. What is the y-component of p\vec{p} in the figure shown before?

Solution

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The position vector\text{\textcolor{#4257b2}{The position vector}}

p=pxi^+pyj^=4i^+3j^\overline{p}=p_x\widehat{i}+p_y\widehat{j}=4\widehat{i}+3\widehat{j}

Therefore the y-component is\text{\textcolor{#c34632}{Therefore the y-component is}} 3j^3\widehat{j}

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