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Question

In the steel bars BEBE and ADAD each have a 6×18mm6 \times 18-\mathrm{mm} cross section. Knowing that E=200 GPaE=200 \mathrm{~GPa}, determine the deflections of points A,BA,B, and CC of the rigid bar ABCABC., the 3.2kN3.2-\mathrm{kN} force caused point CC to deflect to the right. Using α=11.7×106/C\alpha=11.7 \times 10^{-6} /{ }^{\circ} \mathrm{C}, determine (a) the overall change in temperature that causes point CC to return to its original position, (b) the corresponding total deflection of points AA and BB.

Solution

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Answered 1 year ago
Answered 1 year ago
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Let us list down the given data from Problem 9-77.

Given:

  • Cross-sectional area: ABE=AAD=6×18 mmA_{\text{BE}} = A_{\text{AD}} = 6\times18\ \text{mm}
  • Modulus of elasticity: E=200 GPa=200×103 MPaE = 200\ \text{GPa} = 200\times10^{3}\ \text{MPa}
  • Length of AB: LAB=75 mmL_{\text{AB}} = 75\ \text{mm}
  • Length of BC: LBC=300 mmL_{\text{BC}} = 300\ \text{mm}
  • Length of EB: LEB=400 mmL_{\text{EB}} = 400\ \text{mm}
  • Length of AD: LAD=400 mmL_{\text{AD}} = 400\ \text{mm}
  • Load: P=3.2 kN=3200 NP = 3.2\ \text{kN} = 3200\ \text{N}
  • Thermal coefficient: α=11.7×106 C1\alpha = 11.7 \times 10^{-6}\ ^{\circ}\text{C}^{-1}

Required:

a.) Change in temperature needed to revert C to its initial point, ΔT\Delta T

b.) Deflection at A and B due to this change in temperature, δA\delta_{\text{A}} and δB\delta_{\text{B}}

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