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Question

In this exercise, determine the convergence or divergence of the series.

n=1n+1010n+1\displaystyle\sum_{n=1}^{\infty} \frac{n+10}{10 n+1}

Solution

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Answered 2 years ago
Answered 2 years ago

Let an=n+1010n+1a_n=\dfrac{n+10}{10n+1} and consider

limnan=limnn+1010n+1=limn1+10/n10+1/n(Dividing both sides by n)=1+010+0=110\begin{aligned}\lim_{n\rightarrow \infty}a_n&=\lim_{n\rightarrow\infty }\dfrac{n+10}{10n+1}\\&=\lim_{n\rightarrow \infty}\dfrac{1+10/n}{10+1/n}&&(\text{Dividing both sides by }n)\\&=\dfrac{1+0}{10+0}\\&=\dfrac{1}{10}\end{aligned}

Thus we get limnan0\lim_{n\rightarrow \infty}a_n\neq 0 and then using nthn^{th} term test for divergence, we get n=1an=n=1n+1010n+1\sum_{n=1}^{\infty}a_n=\sum_{n=1}^{\infty}\dfrac{n+10}{10n+1} diverges.

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