Try Magic Notes and save time.Try it free
Try Magic Notes and save timeCrush your year with the magic of personalized studying.Try it free
Question

In this given problem using the Law of Cosines to solve the triangle.

β=100,a=22.3,b=16.1\beta=100^{\circ}, a=22.3, b=16.1

Solution

Verified
Answered 2 years ago
Answered 2 years ago
Step 1
1 of 3

First find the angle α\alpha using the Law of Sines:

sinα22.3=sin10016.1sinα=22.3sin10016.1sinα1.36\begin{aligned} \dfrac{\sin\alpha}{22.3}&=\dfrac{\sin100^\circ}{16.1}\\ \sin\alpha&=\dfrac{22.3\cdot\sin100^\circ}{16.1}\\ \sin\alpha&\approx1.36 \end{aligned}

Since the value of sin\sin is less than 11, we cannot find the angle α\alpha. In that case, the triangle does not exist.

Create an account to view solutions

Create an account to view solutions

Recommended textbook solutions

Precalculus 2nd Edition by Carter, Cuevas, Day, Malloy

Precalculus

2nd EditionISBN: 9780076602186Carter, Cuevas, Day, Malloy
8,886 solutions
Precalculus with Limits 3rd Edition by Larson

Precalculus with Limits

3rd EditionISBN: 9781133962885 (3 more)Larson
11,142 solutions
Precalculus with Calculus Previews 6th Edition by Dennis G. Zill, Jacqueline M. Dewar

Precalculus with Calculus Previews

6th EditionISBN: 9781284077261 (1 more)Dennis G. Zill, Jacqueline M. Dewar
4,630 solutions
Precalculus: Mathematics for Calculus 7th Edition by Lothar Redlin, Stewart, Watson

Precalculus: Mathematics for Calculus

7th EditionISBN: 9781305071759 (3 more)Lothar Redlin, Stewart, Watson
9,618 solutions

More related questions

1/4

1/7