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Voici $\rule{1cm}{0.2pt}$ eau minérale.

Lisons Choisis le mot approprie pour completer les phrases.

Vous avez (buvez / beu) de l'eau minérale?

a Are these triangles congruent?

The given triangles are $\triangle ABC$ and $\triangle DEF$. The vertices of the $\triangle ABC$ are at A(-2,-2), B(-2,1), and C(3,-2) while the length of the $\triangle DEF$ are $\overline{DF}$=3, $\overline{DE}$=4, and $\overline{FE}$=5.

A. Yes

B. No

b What if C in the triangle above was at (2,-2)? Would the triangles be congruent in that case?'

A. Yes

B. No

$$\begin{array} { l } { \text { In } \triangle \mathrm { DEF } } \\ { \mathrm { DF } = 6.0 \mathrm { km } } \\ { \angle \mathrm { E } = 44 ^ { \circ } } \\ { \angle \mathrm { F } = 90 ^ { \circ } } \end{array}$$

a) Draw this triangle and label the given information. b) Solve $\triangle \mathrm { DEF }$

If in $\triangle \mathrm{A B C}$ and $\triangle \mathrm{D E F}$, AB = DE, $\mathrm{m} \angle \mathrm{A B C=\mathrm{m} \angle E D F}$, BC = DF, $\mathrm{A C}=(20 x-10)$, and $\mathrm{E F}=(15 x+15)$, what is the value of x?

BC=EF and AC=DF. Are the triangles congruent?

The triangle given are triangles ABC and DEF. The vertices are at A(-3,2), B(-3,4), C(1,4), D(-7,-2), E(-7,0), and (-3,0).

A. Yes

B. No

(a). Draw trapezoid ABCD. Let E and F be points on $\overleftrightarrow{A B}$ such that $\overrightarrow{C E} \perp \overleftrightarrow{A B}$ and $\overrightarrow{D F} \perp \overleftrightarrow{A B}$.

(b). Prove that CE=DF.

($c$). Let AB=$b_1, CD=b_2$, and CE=DF=h. Prove that the area of trapezoid ABCD is $\frac{h}{2}\left(b_1+b_2\right)$.

If a parallelepiped with sides $\overline{DE}, \overline{DF}$, and $\overline{DG}$ has "7ero volume." what can you say about points D, E,F and $G$ ?

Suppose that the differentiable function y=f(x) has an inverse and that the graph of f passes through the point (2,4) and has a slope of 1/3 there. Find the value of df^{-1} / dx at x=4.

Use $\triangle G H J$, where D, E, and F are midpoints of the sides.

If HJ=8x-2 and DF=2x+11, what is HJ?

Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.

$$\cos F$$

Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.

$$\cos D$$

If $F(x, y, z)=\left(5 x^2 y / z^3\right), x=t^{3 / 2}+2, y=\ln 4 t$, and $z=e^{3 t}$, find dF/dt in terms of x,y,z, and t.

Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.

$$\tan F$$