Question

Integrate

secxtanxdx\int \sec x \tan x d x

Solution

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Answered 1 year ago
Answered 1 year ago
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We know that the derivative of the secant function is,

f(x)=secxf(x)=secxtanx\begin{aligned} f(x)&=\sec{x} \\ f'(x)&=\sec{x}\tan{x} \end{aligned}

Therefore, the integral of the expression given in the problem can be solved by,

secxtanxdx=secx+C\begin{aligned} \int{\sec{x}\tan{x}dx}&=\boxed{\sec{x}+C} \end{aligned}

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