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Question

Is cosx\cos x an eigenfunction of the operator A^\hat{A} if A^f(x)=xf(x)\hat{A} f(x)=x f(x) ?

Solution

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Answered 1 year ago
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To be an eigenfunction of an operator O^\hat{O}, a function f(x)f(x) must satisfy the eigenvalue equation:

O^f(x)=af(x)(1)\hat{O}f(x)=af(x)\tag{1}

Where aa is a constant, known as an eigenvalue.

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