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Question

# Jodi says that if you double the radius of a right circular cone and divide the slant height by 2, then the surface area of the cone stays the same since the 2s cancel each other out. How do you respond?

Solution

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Step 1
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## Given:

$r_2 = 2r_1$

$l_2 = \dfrac{l_1}{2}$

## Information:

To solve this exercise we have to recall the equation for the surface area of the right circular cone:

$$$A_s = \pi r^2 + \pi r l$$$

Where $r$ is the radius of the circular base of the cone, and $l$ is the slant height.

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