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Kerosene at 20C20^{\circ} \mathrm{C} flows at 18 m3/h18 \mathrm{~m}^3 / \mathrm{h} in a 55 -cm-diameter pipe. If a 22-cm-diameter thin-plate orifice with corner taps is installed, find the measured pressure drop, in Pa\mathrm{Pa} ?

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In this task I have to find the pressure drop when a 2-cm-diameter thin-plate orifice with corner taps is applied on a 5-cm-diameter pipe. The fluid is Kerosene at 20°C20 \text{\textdegree} C whose properties are:

ρ=804 kgm3μ=1.92103 kgmsν=μρ=1.92103804 m2s=2.388106 m2s\begin{gather*} \rho=804 \ \dfrac{\text{kg}}{\text{m}^3} \\ \mu= 1.92 \cdot 10^{-3} \ \dfrac{\text{kg}}{\text{ms}} \\ \nu= \dfrac{\mu}{\rho}=\dfrac{ 1.92 \cdot 10^{-3} }{804} \ \dfrac{\text{m}^2}{\text{s}}=2.388 \cdot 10^{-6} \ \dfrac{\text{m}^2}{\text{s}} \end{gather*}

The properties of the pipe and the thin-plate orifice are:

Q=18 m3h=5103 m3sD=0.05 mDt=0.02 mβ=DtD=0.020.05=0.4\begin{gather*} Q=18 \ \dfrac{\text{m}^3}{\text{h}}=5 \cdot 10^{-3} \ \dfrac{\text{m}^3}{\text{s}} \\ D=0.05 \ \text{m} \\ D_t=0.02 \ \text{m} \\ \beta = \dfrac{D_t}{D}=\dfrac{0.02}{0.05}=0.4 \end{gather*}

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