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Question

Let f(x) = 3x + 1 and

g(t)=t22t+1g ( t ) = t ^ { 2 } - 2 t + 1

. Find the value. f(r + 8)

Solution

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Step 1
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To determine the value, substitute r+8r+8 with xx in the equation and evaluate:

f(r+8)=3(r+8)+1f(r+8)=3r+24+1\begin{align*} f(r+8) &= 3(r+8)+1\\ f(r+8) &= 3r+24+1 \end{align*}

f(r+8)=3r+25\fbox{$f(r+8)=3r+25$}

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