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Question

Match the trigonometric expression with its simplified form. (a) sec x, (b) -1 (c) cot x, (d) 1, (e) -tan x, (f) sin x. sin(x)cos(x)\frac{\sin (-x)}{\cos (-x)}

Solution

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Answered 2 years ago
Answered 2 years ago
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We know:  x, sin(x)=sinx, cos(x)=cosx\ \forall x, \ \sin(-x)=-\sin x, \ \cos (-x)=\cos x.

So,

sin(x)cos(x)=sinxcosx=tanx\begin {aligned} \frac {\sin (-x) } {\cos (-x) }&=\frac {-\sin x } { \cos x} \\[12pt] &=\boxed {-\tan x } \end {aligned}

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