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In given problem, find div F\mathbf{F} and curl F\mathbf{F}.

F(x,y,z)=(y+z)i+(x+z)j+(x+y)k\mathbf{F}(x, y, z)=(y+z) \mathbf{i}+(x+z) \mathbf{j}+(x+y) \mathbf{k}

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Answered 2 years ago
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F=x,y,zM,N,P=Mx+Ny+Pz=x(y+z)+y(x+z)+z(x+y)=0+0+0=0\begin{align*} \nabla\cdot\mathbf{F} &= \left\langle\dfrac{\partial}{\partial x},\dfrac{\partial}{\partial y},\dfrac{\partial}{\partial z}\right\rangle \cdot \left\langle M,N,P\right\rangle\\ &= \dfrac{\partial M}{\partial x} + \dfrac{\partial N}{\partial y} + \dfrac{\partial P}{\partial z}\\ &=\dfrac{\partial}{\partial x}(y+z)+\dfrac{\partial}{\partial y}(x+z)+\dfrac{\partial}{\partial z}(x+y)\\ &=0+0+0\\ &=0 \end{align*}

Calculate the divergence of F\mathbf{F}.

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