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Maximize Z=14x+21y subject to

2x+3y12x+5y8x,y0\begin{aligned} 2 x+3 y & \leq 12 \\ x+5 y & \leq 8 \\ x, y & \geq 0 \end{aligned}

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Answered 2 years ago
Answered 2 years ago
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{ Graph the feasible set.

} Graph the line 2x+3y=122x+3y=12,      using (0,4)(0,4) and (6,0)(6, 0).

The coordinates of the origin satisfy the inequality 2x+3y122x+3y\leq 12,

so we shadow the half-plane that does not contain the origin.

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