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Methane (CH4)\left(\mathrm{CH}_4\right) at 25C,1 atm25^{\circ} \mathrm{C}, 1 \mathrm{~atm} enters a furnace operating at steady state and burns completely with 140%140 \% of theoretical air entering at 400 K,1 atm400 \mathrm{~K}, 1\ \text{atm}. The products of combustion exit at 700 K,1 atm700 \mathrm{~K}, 1 \mathrm{~atm}. Kinetic and potential energy effects are negligible. If the rate of heat transfet from the furnace to the surroundings is 400 kW400 \mathrm{~kW}, determine the mass flow rate of methane, in kg/s\mathrm{kg} / \mathrm{s}.

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Answered 2 years ago
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Write the balanced chemical equation of CH4CH_4 for complete combustion with theoretical amount of dry air

CH4+α(O2+3.76N2)βCO2+γH2O+ωN2CH_4+ \alpha (O_2+3.76N_2)\rightarrow \beta CO_2+\gamma H_2O+\omega N_2

( \therefore 3.76 moles of N2N_2 accompany each mole of O2O_2 in the air)

By applying conservation of mass principle to carbon hydrogen Oxygen and nitrogen respectively.

C : β=1\rightarrow \beta= 1

H : 2γ=4\rightarrow 2 \gamma=4

O : 2α=2β+γ\rightarrow 2 \alpha=2 \beta+\gamma

N2N_2 : α(3.76)=ω\rightarrow \alpha(3.76)=\omega

By solving,

α=2\alpha = 2

β=1\beta=1

γ=2\gamma=2

ω=7.52\omega=7.52

Therefore the balanced chemical equation is,

CH4+2(O2+3.76N2)CO2+2H2O+7.52N2CH_4+ 2 (O_2+3.76N_2) \rightarrow CO_2+2 H_2O+7.52 N_2

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