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Question

Nitrogen at 900 kPa900\ \mathrm{kPa} and 300C300^{\circ} \mathrm{C} is expanded adiabatically in a closed system to 100 kPa100\ \mathrm{kPa}. Find the minimum nitrogen temperature after the expansion.

Solution

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Answered 2 years ago
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Nitrogen is an ideal gas. To obtain the final temperature when nitrogen is expanded isentropically we will use the isentropic relation of an ideal gas under constant specific heat assumption.

T2T1=(P2P1)(k1)/k\frac{T_{2}}{T_1}=\left(\frac{P_{2}}{P_{1}}\right)^{(k-1) / k}

Since we don't know the final temperature yet, we will assume that the average temperature is 450450 K. The specific heat ratio of nitrogen can be found in Table A-2b to be k=1.391k=1.391. Thus the final temperature is:

T2=T1(P2P1)(k1)/k=(300+273 K)(100kPa900kPa)0.391/1.391=309 K\begin{aligned} T_{2} &=& T_{1}\left(\frac{P_{2}}{P_{1}}\right)^{(k-1) / k}\\ &=& (300+273 \mathrm{~K})\left(\frac{100 \mathrm{kPa}}{900 \mathrm{kPa}}\right)^{0.391 / 1.391}\\ &=& \boxed{309 \mathrm{~K}} \end{aligned}

The actual average air temperature is 441441 K, therefore our assumed average temperature of 450 K is good enough.

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