First the general reaction for the excess amount of air is written as follows:
C8H18+1.8a(O2+3.76N2)−>bCO2+cH2O+0.8aO2+dN2
An analysis of the reaction gives the following values for the coefficients:
a=12.5b=8c=9d=84.6
The reaction is then:
C8H18+22.5(O2+3.76N2)−>8CO2+9H2O+10O2+84.6N2
The additional amount of water is obtained by first determining the pressure of the water vapor in the products. The saturation pressure at the given temperature is taken from A-4:
PH2O=ϕPsat, 25=0.4⋅3.1698kPa=1.268kPa
The amount of the additional water vapor is then:
NH2O=PPH2ONNH2O=PPH2O(Ndry+NH2ONH2O=101.3251.268(4.76⋅22.5+NH2ONH2O=1.36kmol
The final form of the reaction then is:
C8H18+22.5(O2+3.76N2)+1.36H2O−>8CO2+10.36H2O+10O2+84.6N2
The heat transfer is determined from the enthalpies of formation and the molar enthalpies which are obtained from A-18 to A-26 for the given temperatures:
Q=(N(hf°°+h−h°°))reac−(N(hf°°+h−h°°))prod=(1(−208450)+1.36(−241820)−8(−393520+42769−9364)−10.36(−241820+35882−9904)−10(0+31389−8682)−84.6(0+30129−8669))kmolkJ=2537132kmolkJ