Question
Often a radical change in the solution of a differential equation corresponds to a very small change in either the initial condition or the equation itself. Compare the solutions of the given initial-value problems.
Solution
VerifiedStep 1
1 of 2Solution of initial value problem is
By variable separable we can write as
Integration will be
Now, value of constant is by using initial value problem
Here, we can see there is no specific value of there is only value of which satisfy above initial condition
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