Question

On what interval is the curve y = ∫x 0 t^2/t^2+t+2 dt

Solution

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Answered 6 months ago
5 (24 ratings)
Answered 6 months ago
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y=0xt2t2+t+2  dt\displaystyle y = \int_0^x \dfrac{t^2}{t^2+t+2} \; dt

yy is concave down in the intervals where yy' is decreasing

y=x2x2+x+2y' = \dfrac{x^2}{x^2+x+2}

Find where y<0y'' < 0 to find when yy' is decreasing

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