## Related questions with answers

One can get a rough estimate of the energy released in fission by considering the above figure, which shows the potential energy of the two fragments. The energy released is roughly the potential energy at $x=x_0$, which, in turn, is roughly $k q_1 q_2 / x_0$. (Both of these approximations will actually be overestimates.) Taking $x_0 \sim 12 \mathrm{fm}$, estimate the energy released in the fission ${ }^{236} \mathrm{U} \rightarrow{ }^{92} \mathrm{Kr}+{ }^{144} \mathrm{Ba}$.

Solution

VerifiedFigure 17.14 shows that at large distances, the dominant force between two nuclei is the Coulomb force peaking at a certain distance $x_0$. We estimate that the potential energy at this distance is roughly equal to the energy released in a fission reaction as the one below.

$^{236}\text{U}\rightarrow^{92}\text{Kr}+^{144}\text{Ba}$

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