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Particle accelerators, such a s the Large Hadron Collider, use magnetic fields to steer charged particles a round a ring. Consider a proton ring with 36 identical bending mag nets connected by straight segments. The protons move along a 1.0-m-long circular arc as they pass through each magnet. What magnetic field strength is needed i n each magnet to steer protons around the ring with a speed of 2.5×107m/s2.5 \times 10^{7} \mathrm{m} / \mathrm{s}? Assume that the field is uniform inside the magnet, zero outside.

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The cyclotron motion is the moving of a particle perpendicular to the magnetic field in a uniform circular motion with constant speed. The circular motion is produced by the magnetic field is related to the radius of the motion by equation (29.20) in the form

rcyc=mvqB\begin{equation} r_{\mathrm{cyc}}=\frac{m v}{q B} \end{equation}

Where qq is the charge of the particle, vv is the speed of the particle, BB is the magnetic field and mm is the mass of the particles. The length of one magnet is 1 m, so for a circular path of 36 magnets, the length of the path will be LL = 1 m ×36\times 36 = 36 m which represents the circumference of the path. So, we can use it to get the radius of the motion by

L=2πrcycrcyc=L2π=36 m2πrcyc=5.73 m\begin{gather*} L = 2 \pi r_{\mathrm{cyc}}\\ r_{\mathrm{cyc}} = \frac{L}{2\pi} = \frac{36 \mathrm{~m}}{2\pi}\\ r_{\mathrm{cyc}} = 5.73 \mathrm{~m} \end{gather*}

Our target is to find the required magnetic field, so we rearrange equation (1) for BB to be

B=mvqrcyc\begin{equation} B=\frac{m v}{q r_{\mathrm{cyc}}} \end{equation}

Now, we plug the values for m,v,qm,v,q and rcycr_{\mathrm{cyc}} into equation (2) tp get BB by

B=mvqrcyc=(1.67×1027 kg)(2.5×107 m/s)(5.73 m)(1.6×1019 C)=45.5×103 T=45.5 mT\begin{align*} B&=\frac{m v}{q r_{\mathrm{cyc}}}\\ &= \frac{\left(1.67 \times 10^{-27} \mathrm{~kg}\right)\left(2.5 \times 10^{7} \mathrm{~m} / \mathrm{s}\right)}{(5.73 \mathrm{~m})\left(1.6 \times 10^{-19} \mathrm{~C}\right)}\\ &= 45.5 \times 10^{-3} \mathrm{~T}\\ &= \boxed{45.5 \mathrm{~mT}} \end{align*}

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