## Related questions with answers

Previous exercise gave the summary data (x = 27.8, s = 32.2 spikes per second) for the baseline activity of a neuron based on 72 separate recordings. Neural activity is expressed in number of action potentials per second and cannot be less than 0. You notice that the standard deviation is larger than the mean. What does it suggest about the shape of the distribution? Is it nonetheless acceptable to calculate a t confidence interval for the population mean? Explain why.

Solution

VerifiedThe distribution is right-skewed, because the values can only by nonnegative and the sample standard deviation is greater than the sample mean.

It is acceptable to calculate a $t$ confidence interval for the population mean, because the sample size is 30 or more and the sampling distribution of the sample mean is then roughly normally distributed.

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