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Question

Prof. Garcia polled his students to determine the number of hours per week they spent on homework for his course. Here are his findings:

3.507.509.002.253.505.254.002.754.751.504.503.503.258.502.755.500.255.752.256.255.006.003.504.000.752.253.503.754.006.50\begin{array}{cccccc}{3.50} & {7.50} & {9.00} & {2.25} & {3.50} & {5.25} \\ {4.00} & {2.75} & {4.75} & {1.50} & {4.50} & {3.50} \\ {3.25} & {8.50} & {2.75} & {5.50} & {0.25} & {5.75} \\ {2.25} & {6.25} & {5.00} & {6.00} & {3.50} & {4.00} \\ {0.75} & {2.25} & {3.50} & {3.75} & {4.00} & {6.50}\end{array}

Summarize this information with a histogram with

Solution

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Answered 2 years ago
Answered 2 years ago
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First, let's divide the given data into five categories and write in a table. The smallest number in the given data is 0.2500.25\approx0 and the biggest number is 9.00109.00\approx10, we use this information to define the category limits.

Hours per week Numbers in the Interval
020-2 1.50,0.25,0.751.50,0.25,0.75
2.0142.01-4 3.50,2.25,3.50,2.75,3.50,3.25,2.75,2.25,3.50,4.00,2.25,3.50,3.75,4.003.50,2.25,3.50,2.75,3.50,3.25,2.75,2.25,3.50,\\4.00,2.25,3.50,3.75,4.00
4.0164.01-6 5.25,4.00,4.75,4.50,5.50,5.75,5.00,6.005.25,4.00,4.75,4.50,5.50,5.75,5.00,6.00
6.0186.01-8 7.50,6.25,6.507.50,6.25,6.50
8.01108.01-10 9.00,8.509.00,8.50

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