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Propane gas (C3H8)(C_3H_8) at 25C,25^\circ C, 1 atm enters a reactor operating at steady state and burns with 20% excess au entering at 25C,25^\circ C, 1 atm. Of the carbon entering with the fuel, 94% (molar basis) appears in the products as CO2CO_2 and the rest as CO. Heat transfer from the reactor occurs at a rate of 1.4×106kJ1.4 \times 10^6 kJ per kmol of propane. Ignoring kinetic and potential energy effects, determine the temperature of the combustion products exiting the reactor, in K.

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The ratio of NX2\ce{N2} to OX2\ce{O2} in air is,

nNX2nOX2=0.790.21=3.76\begin{align*} \dfrac{n_{\ce{N2}}}{n_{\ce{O2}}} &= \dfrac{0.79}{0.21} \\ &= 3.76 \end{align*}

The chemical reaction is,

CX3HX8+x (OX2+3.76NX2)aCOX2+bHX2O+3.76xNX2\ce{C3H8 + x (O2 + 3.76 N2) -> a CO2 + b H2O + 3.76x N2}

The mass balance of C is:

3=a\begin{align*} 3 &= a \end{align*}

The mass balance of H is:

8=2b4=b\begin{align*} 8 &= 2b \\ 4 &= b \end{align*}

The mass balance of O is:

2x=2a+b2x=6+4x=5\begin{align*} 2x &= 2a + b \\ 2x &= 6 + 4 \\ x &= 5 \end{align*}

Substitute in the chemical reaction,

CX3HX8+5(OX2+3.76NX2)3COX2+4HX2O+18.8NX2\ce{C3H8 + 5 (O2 + 3.76 N2) -> 3 CO2 + 4 H2O + 18.8 N2}

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