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Prove that if p ones and q zeros are placed around a circle in an arbitrary manner, where p, q, and k are positive integers satisfying pkq, the arrangement must contain at least k consecutive ones.
Solution
VerifiedGiven:
ones and zeros are placed arbitrarily about a circle
are positive integers with
To proof: The arrangement contains at least consecutive ones.
Let us assume, for the sake of contradiction, that there are not at least consecutive ones.
Since there are zeros and since there are not at least consecutive ones, there are at most ones between each pair of consecutive zeros.
Since there are pairs of consecutive zeros with at most pairs of consecutive ones between them, there are at most ones placed about the circle.
However, we placed ones about the circle which is more than ones as and thus we derived a contradiction.
This then implies that out assumption "there are not at least consecutive ones" is incorrect and thus there are at leat consecutive ones in the arrangement.
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