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Q(0, 7, −6) and M(−1, 3, 2), where M is the midpoint of the line segment PQ

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Answered 9 months ago
Answered 9 months ago
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Let P=(x,y,z)P=(x,y,z) be the initial point.

Given that Q=(0,7,6)Q=(0,7,-6) be the terminal point and M=(1,3,2)M=(-1,3,2) be the mid point of the line segment PQPQ.

Therefore,

(x+02,y+72,z62)=(1,3,2)    x2=1, y+72=3, z62=2    x=2, y+7=6, z6=4    x=2, y=1, z=10\begin{aligned} &\left(\dfrac{x+0}{2},\dfrac{y+7}{2},\dfrac{z-6}{2}\right)=(-1,3,2)\\ \implies&\dfrac{x}{2}=-1,~\dfrac{y+7}{2}=3,~\dfrac{z-6}{2}=2\\ \implies&x=-2,~y+7=6,~z-6=4\\ \implies& x=-2,~y=-1,~z=10 \end{aligned}

So, the initial P=(2,1,10)P =(-2,-1,10).

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