## Related questions with answers

R134a is flowed into an insulated 0.2-m3 initially empty container from a line at 500 kPa, saturated vapor until the flow stops by itself. Find the final mass and temperature in the container and the total irreversibility in the process.

Solution

VerifiedWe are given following data for R-134a flowed into empty container:

$P=500\text{ kPa}$

$V=0.2\text{ m}^3$

From Superheated R-134a table B.5.2. corresponding to $P_1=500\text{ kPa}$ we can find stage 1 saturated vapor specific entropy and enthalpy:

$h_1=407.45\frac{\text{ kJ}}{\text{ kg}}$

$s_1=1.7198\frac{\text{ kJ}}{\text{ kg K}}$

$T_1=T_{amb}=15.66\text{ C}=289\text{ K}$

From energy equation we know that inlet enthalpy is equal to exit specific internal energy:

$u_2=h_1=407.45\frac{\text{ kJ}}{\text{ kg}}$

From Superheated R-134a table B.5.2. corresponding to $P_2=500\text{ kPa}$ and $u_2=407.45\frac{\text{ kJ}}{\text{ kg}}$ we can find stage 2 specific entropy, volume and temperature:

$\nu_2=0.04656\frac{\text{ m}^3}{\text{ kg}}$

$s_2=1.7971\frac{\text{ kJ}}{\text{ kg K}}$

$T_2=\boxed{40\text{ C}}$

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