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R134a is flowed into an insulated 0.2-m3 initially empty container from a line at 500 kPa, saturated vapor until the flow stops by itself. Find the final mass and temperature in the container and the total irreversibility in the process.

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Answered 2 years ago
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We are given following data for R-134a flowed into empty container:

P=500 kPaP=500\text{ kPa}

V=0.2 m3V=0.2\text{ m}^3

From Superheated R-134a table B.5.2. corresponding to P1=500 kPaP_1=500\text{ kPa} we can find stage 1 saturated vapor specific entropy and enthalpy:

h1=407.45 kJ kgh_1=407.45\frac{\text{ kJ}}{\text{ kg}}

s1=1.7198 kJ kg Ks_1=1.7198\frac{\text{ kJ}}{\text{ kg K}}

T1=Tamb=15.66 C=289 KT_1=T_{amb}=15.66\text{ C}=289\text{ K}

From energy equation we know that inlet enthalpy is equal to exit specific internal energy:

u2=h1=407.45 kJ kgu_2=h_1=407.45\frac{\text{ kJ}}{\text{ kg}}

From Superheated R-134a table B.5.2. corresponding to P2=500 kPaP_2=500\text{ kPa} and u2=407.45 kJ kgu_2=407.45\frac{\text{ kJ}}{\text{ kg}} we can find stage 2 specific entropy, volume and temperature:

ν2=0.04656 m3 kg\nu_2=0.04656\frac{\text{ m}^3}{\text{ kg}}

s2=1.7971 kJ kg Ks_2=1.7971\frac{\text{ kJ}}{\text{ kg K}}

T2=40 CT_2=\boxed{40\text{ C}}

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