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Question

Reagan's school is selling tickets to a spring musical. On the first day of ticket sales, the school sold 3 senior citizen tickets and 9 child tickets for a total of $75. The school took in$67 on the second day by selling 8 senior citizen tickets and 5 child tickets. What is the price of each ticket?

Solution

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Let ss be the price of each senior ticket and cc be the price of each child ticket.

On the first day, they sold 3 senior tickets so they earned 3s3s dollars for the senior tickets. They sold 9 child tickets so they earned 9c9c dollars for the senior tickets. The total amount they earned was then 3s+9c3s+9c dollars. Since they earned $75 on the first day, then 3s+9c=753s+9c=75. Dividing both sides by 3 then gives s+3c=25s+3c=25.

On the second day, they sold 8 senior tickets so they earned 8s8s dollars for the senior tickets. They sold 5 child tickets so they earned 5c5c dollars for the senior tickets. The total amount they earned was then 8s+5c8s+5c dollars. Since they earned $67 on the second day, then 8s+5c=678s+5c=67.

Since the first equation can be easily solved for ss, use the substitution method to solve the system of equations. Solving s+3c=25s+3c=25 for ss gives s=253cs=25-3c.

Substitute s=253cs=25-3c into the second equation and solve for cc:

8s+5c=678(253c)+5c=67Substitute.20024c+5c=67Distribute.20019c=67Combine like terms.19c=133Subtract 200 on both sides.c=7Divide both sides by 19.\begin{aligned} 8s+5c&=67\\ 8(25-3c)+5c&=67&&\text{Substitute.}\\ 200-24c+5c&=67&&\text{Distribute.}\\ 200-19c&=67&&\text{Combine like terms.}\\ -19c&=-133&&\text{Subtract 200 on both sides.}\\ c&=7&&\text{Divide both sides by $-19$.} \end{aligned}

The price of each child ticket is then c=$7c=\boxed{\$7} and the price of each senior ticket is s=253c=253(7)=2521=$4s=25-3c=25-3(7)=25-21=\boxed{\$4}.

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