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In a police forensics lab, you examine a package that may contain heroin. However, you find the white powder is not pure heroin but a mixture of heroin (C21H23O5 N)\left(\mathrm{C}_{21} \mathrm{H}_{23} \mathrm{O}_5 \mathrm{~N}\right) and lactose (C12H22O11)\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right). To determine the amount of heroin in the mixture, you dissolve 1.00 g1.00 \mathrm{~g} of the white powdery mixture in water in a 100.0mL100.0-\mathrm{mL} volumetric flask. You find that the solution has an osmotic pressure of 539 mmHg539 \mathrm{~mm} \mathrm{Hg} at 25C25^{\circ} \mathrm{C}. What is the composition of the mixture?

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It is a given sample that is a mixture of heroin and lactose. The sample is dissolved in water.

The task is to determine the composition of the mixture.

Given data: m(mixture) = 1g V(water) = 100 mL = 0.1 L Π\Pi = 539 mmHg = 0.709atm T = 25°\degreeC = 298K

We need to know the molar mass of compounds: Mr(heroin) = 369.4 g/mol Mr(lactose) = 342.3 g/mol

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