Question

# Repeat Problem 41 with the second 3.0-kg block replaced by a $5.0-\mathrm{kg}$ block moving to the right at $3.0 \mathrm{~m} / \mathrm{s}$.

Solution

Verified
\begin{aligned} m_1 & = 3.0\text{ kg}\\ m_2 & = 5.0\text{ kg}\\ v_1 & = 5.0\mathrm{~\dfrac{m}{s}}\\ v_2 & = 3.0\mathrm{~\dfrac{m}{s}}\\ \end{aligned}