Question

Repeat Problem 41 with the second 3.0-kg block replaced by a 5.0kg5.0-\mathrm{kg} block moving to the right at 3.0 m/s3.0 \mathrm{~m} / \mathrm{s}.

Solution

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Answered 1 year ago
Answered 1 year ago
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(a) In this part of the problem, we are asked to calculate the total kinetic energy of the two blocks. The known values are given as follows:

m1=3.0 kgm2=5.0 kgv1=5.0 msv2=3.0 ms\begin{aligned} m_1 & = 3.0\text{ kg}\\ m_2 & = 5.0\text{ kg}\\ v_1 & = 5.0\mathrm{~\dfrac{m}{s}}\\ v_2 & = 3.0\mathrm{~\dfrac{m}{s}}\\ \end{aligned}

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