## Related questions with answers

Question

Repeat Problem when the materials are surrounded by water.

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 2In order to solve this problem we are going to employ the definition of the critical angle. It says that

$\sin\theta_c=\frac{n_2}{n_1}$

and it gives that

$\theta_c=\arcsin{\frac{n_2}{n_1}}$

a) In the case of diamond surrounded by water we have that

$\theta_c=\arcsin{\frac{n_2}{n_1}}=\arcsin{\frac{1.333}{2.419}}$

$\theta_c=33.4^\circ$

b) In the case of flint glass surrounded by water we have that

$\theta_c=\arcsin{\frac{n_2}{n_1}}=\arcsin{\frac{1.333}{1.66}}$

$\theta_c=53.4^\circ$

c) In the case of ice surrounded by water we have that $n_2>n_1$ so there is no critical angle.

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