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Requests to a Web server. In Exercise 4.1754.175 (p. 258) you learned that Brighton Webs LTD modeled the arrival time of requests to a Web server within each hour, using a uniform distribution. Specifically, the number of seconds xx from the start of the hour that the request is made is uniformly distributed between 0 and 3,600 seconds. In a random sample of n=60n=60 Web server requests, let xˉ\bar{x} represent the sample mean number of seconds from the start of the hour that the request is made. Find the probability that xˉ\bar{x} is between 1,700 and 1,900 seconds.

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Answered 1 year ago
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Given:

n=Sample size=60\begin{align*} n&=\text{Sample size}=60 \end{align*}

xx has a uniform distribution between 0 and 3600.

a=0b=3600\begin{align*} a&=0 \\ b&=3600 \end{align*}

We need to determine the probability P(1700<x<1900)P(1700<\overline{x}<1900).

To derive the probability, the sample means x\overline{x} need to be converted to z-scores and then determine the probability using the normal distribution.

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