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Show that

df=y(1+xx2)dx+x(x+1)dyd f=y\left(1+x-x^2\right) d x+x(x+1) d y

is not an exact differential. Find the differential equation that a function g(x)g(x) must satisfy if dϕ=g(x)dfd \phi=g(x) d f is to be an exact differential. Verify that g(x)=exg(x)=e^{-x} is a solution of this equation and deduce the form of ϕ(x,y)\phi(x, y).

Solution

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Answered 2 years ago
Answered 2 years ago
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Differential equation is:

df= Adx+ Bdy

To check whether the equation is exact differential equation or not :

Ay=Bx\dfrac{\partial A}{\partial y}= \dfrac{\partial B}{\partial x}

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