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Question

Show that isomorphism of simple graphs is an equivalence relation.

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DEFINITIONS

Two simple graphs G1=(V1,E1)G_1=(V_1,E_1) and G2=(V2,E2)G_2=(V_2,E_2) are isomorphic\textbf{isomorphic} if there exists a one-to-one and onto function f:V1V2f:V_1\rightarrow V_2 such that aa and bb are adjacent in G1G_1 if and only if f(a)f(a) and f(b)f(b) are adjacent in G2G_2.

A relation RR is an equivalence relation\textbf{equivalence relation} if the relation RR is transitive, symmetric and reflexive.

A relation RR on a set AA is reflexive\textbf{reflexive} if (a,a)R(a,a)\in R for every element aAa\in A.

A relation RR on a set AA is symmetric\textbf{symmetric} if (b,a)R(b,a)\in R whenever (a,b)R(a,b) \in R

A relation RR on a set AA is transitive\textbf{transitive} if (a,b)R(a,b)\in R and (b,c)R(b,c) \in R implies (a,c)R(a,c)\in R

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