Try Magic Notes and save time.Try it free
Try Magic Notes and save timeCrush your year with the magic of personalized studying.Try it free
Question

Show that the expression for the period of a physical pendulum reduces to that of a simple pendulum if the physical pendulum consists of a particle with mass mm on the end of a massless string of length LL.

Solution

Verified
Answered 2 years ago
Answered 2 years ago
Step 1
1 of 5

A physical pendulum is pivoted at a fixed point. When the pendulum is in its equilibrium position, then its center of mass is directly under its pivot point. However, when it is displaced from equilibrium by an angle θ\theta, a restoring torque acts on it in the opposite direction of its motion.

τ=(mg)(Lsinθ)\begin{align*} \tau &=-\left( mg \right)\left( L\sin \theta \right)\\ \end{align*}

Where,

m=m= mass of physical pendulum

L=L= distance of pivot point from center of mass

Create an account to view solutions

Create an account to view solutions

Recommended textbook solutions

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics 4th Edition by Randall D. Knight

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th EditionISBN: 9780133942651 (4 more)Randall D. Knight
3,508 solutions
University Physics with Modern Physics 12th Edition by Hugh D. Young, Roger A. Freedman

University Physics with Modern Physics

12th EditionISBN: 9780321501219 (12 more)Hugh D. Young, Roger A. Freedman
7,310 solutions
Mathematical Methods in the Physical Sciences 3rd Edition by Mary L. Boas

Mathematical Methods in the Physical Sciences

3rd EditionISBN: 9780471198260Mary L. Boas
3,355 solutions
Fundamentals of Physics 10th Edition by David Halliday, Jearl Walker, Robert Resnick

Fundamentals of Physics

10th EditionISBN: 9781118230718David Halliday, Jearl Walker, Robert Resnick
8,971 solutions

More related questions

1/4

1/7