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Question

Show that the mean free path for a molecule in an ideal gas at temperature TT and pressure PP is given by λ=kT/(2Pπd2)\lambda=k T /\left(\sqrt{2} P \pi d^2\right).

Solution

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Answered 1 year ago
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In this problem, we need to prove following relation:

λ=KT2πd2P\lambda = \frac{KT}{\sqrt{2}\pi d^2 P}

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