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Question

Let $V$ be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose $P (V) = 0.15$, $P (W) = 0.05$, and $P (V\ \text{and}\ W) = 0.03$.

$\textbf{a.}\hspace{10pt}$ Find the probability that the computer contains either a virus or a worm or both.

$\textbf{b.}\hspace{10pt}$ Find the probability that the computer does not contain a virus.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 8**(a)**

To determine the probability that the computer that has either a virus or a worm or both we will use the general addition rule.

$P(V \ \text{or} \ W)=P(V)+P(W)-P(V \ \text{and} \ W)$

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