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Question

Let VV be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V)=0.15P (V) = 0.15, P(W)=0.05P (W) = 0.05, and P(V and W)=0.03P (V\ \text{and}\ W) = 0.03.

a.\textbf{a.}\hspace{10pt} Find the probability that the computer contains either a virus or a worm or both.

b.\textbf{b.}\hspace{10pt} Find the probability that the computer does not contain a virus.

Solution

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(a)

To determine the probability that the computer that has either a virus or a worm or both we will use the general addition rule.

P(V or W)=P(V)+P(W)P(V and W)P(V \ \text{or} \ W)=P(V)+P(W)-P(V \ \text{and} \ W)

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