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Question

Simplify. Identify any x-values for which the expression is undefined.

6x3+6xx2+1\frac { 6 x ^ { 3 } + 6 x } { x ^ { 2 } + 1 }

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6x3+6xx2+1=6xx2+6x1x2+1=6x(x2+1)x2+1=6x\begin{align*}\dfrac{6\cdot x^3+6\cdot x}{x^2+1} &=\dfrac{6\cdot x\cdot x^2+6\cdot x\cdot 1}{x^2+1} \\ &=\dfrac{6\cdot x\cdot \cancel{(x^2+1)}}{\cancel{x^2+1}} \tag{ factore out $6\cdot x$ in numerator}\\ &={\color{#4257b2} 6\cdot x} \tag{ cancel $x^2 +1$} \end{align*}

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