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Question

Simplify the expression.

(a2)3(a3b)2(b3)4\left( a ^ { 2 } \right) ^ { - 3 } \left( a ^ { 3 } b \right) ^ { 2 } \left( b ^ { 3 } \right) ^ { 4 }

Solution

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Using laws of exponents, then

(a2)3(a3b)2(b3)4a6a6b2b12=a6+6b2+12=a0b14=b14.\begin{align*} (a^2)^{-3}(a^3b)^2(b^3)^4 &\rightarrow a^{-6}a^6b^2b^{12} \\\\&= a^{-6+6}b^{2+12} \\\\&= a^0b^{14} \\\\&= b^{14} .\end{align*}

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