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Question

Simplify the expression.

(x2y3)5\left(\frac{x^{2}}{y^{3}}\right)^{-5}

Solution

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Recall that: (ab)n=(ba)n\text{\color{#4257b2}Recall that: $\left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}$}

(x2y3)5=(y3x2)5\left(\dfrac{x^2}{y^3}\right)^{-5} =\left(\dfrac{y^3}{x^2}\right)^{5}

Recall that: (ab)n=anbn\text{\color{#4257b2}Recall that: $\left(\dfrac{a}{b}\right)^{n}=\dfrac{a^n}{b^n}$}

=(y3)5(x2)5=\dfrac{(y^3)^5}{(x^2)^5}

Recall that: (am)n=amn\text{\color{#4257b2}Recall that: $(a^m)^n=a^{m\cdot n}$}

=y35x25=\dfrac{y^{3\cdot5}}{x^{2\cdot5}}

=y15x10=\dfrac{y^{15}}{x^{10}}

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