Try Magic Notes and save time.Try it free
Try Magic Notes and save timeCrush your year with the magic of personalized studying.Try it free
Question

Sketch the graph of the function in previous question. Show that the slope of the tangent can be found using the properties of circles.

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 3

We have the function

y=25x2y=\sqrt{25-x^2}

and the point P(3,4)P\left(3,4\right)

We will change the form of our function. We will turn it into a circle equation as follows:

y=25x2y2=25x2x2+y2=25\begin{align*} y&=\sqrt{25-x^2}\\ y^2&=25-x^2\\ x^2+y^2&=25\\ \end{align*}

This is the equation of a circle that has a center at the origin of the coordinate system and a radius 55.

Create an account to view solutions

Create an account to view solutions

Recommended textbook solutions

Thomas' Calculus 14th Edition by Christopher E Heil, Joel R. Hass, Maurice D. Weir

Thomas' Calculus

14th EditionISBN: 9780134438986 (4 more)Christopher E Heil, Joel R. Hass, Maurice D. Weir
10,144 solutions
Calculus and Vectors 1st Edition by Robert Donato

Calculus and Vectors

1st EditionISBN: 9780176374440Robert Donato
1,548 solutions
Calculus: Early Transcendentals 8th Edition by James Stewart

Calculus: Early Transcendentals

8th EditionISBN: 9781285741550 (1 more)James Stewart
11,085 solutions
Calculus: Early Transcendentals 9th Edition by Daniel K. Clegg, James Stewart, Saleem Watson

Calculus: Early Transcendentals

9th EditionISBN: 9781337613927 (3 more)Daniel K. Clegg, James Stewart, Saleem Watson
11,049 solutions

More related questions

1/4

1/7