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Sketch the solid described by the given inequalities. 0<=r<=2, -pi/2<=theta<=pi/2, 0<=z<=1

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First focus on rz2r\leq z\leq2

r=zr = z is z=x2+y2z = \sqrt{x^2+y^2}, this is a cone

z=2z=2 is a plane.

rz2r\leq z\leq 2 is region below the plane z=2z=2, but above the cone z=rz=r

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