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Question

Sketch the solutions of the differential equations in Exercise given below. In each case, also indicate the constant solutions.

y=y2+y,y(0)=13y^{\prime}=y^2+y, y(0)=-\frac{1}{3}

Solution

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Answered 2 years ago
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Consider the differential equation

y=g(y)y'=g(y)

where g(y)=y2+y=y(y+1)g(y)=y^2+y=y(y+1).

Note that for the zeros of g(y)g(y) we have:

y(y+1)=0    y=0y=1y(y+1)=0 \implies y=0 \quad \lor \quad y=-1

Then, the differential equation y=g(y)y'=g(y) has the constant solutions y=0y=0 and y=1y=-1.

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