## Related questions with answers

Software analysis of the salaries of a random sample of 288 Nevada teachers produced the confidence interval shown below. Which conclusion is correct? What’s wrong with the others?

$\text { t-Inter val for } \mu : \left. \begin{array} { c c } { \text {with } 90.00 \% \text { Confidence, } } \\ { } { 38944 < \mu [ \text { TchPay]} < 42893 } \end{array} \right.$

a) If we took many random samples of 288 Nevada teachers, about 9 out of 10 of them would produce this confidence interval. b) If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce a confidence interval that contained the mean salary of all Nevada teachers. c) About 9 out of 10 Nevada teachers earn between $38,944 and$42,893. d) About 9 out of 10 of the teachers surveyed earn between $38,944 and$42,893. e) We are 90% confident that the average teacher salary in the United States is between $38,944 and$42,893.

Solution

Verifieda) Incorrect, because almost all random samples will result in different confidence intervals and thus it is not possible that 9 out of 10 have the same confidence interval.

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