Try the fastest way to create flashcards
Question

# Solve. 3y + 4y + 6 = 20

Solution

Verified
Step 1
1 of 4

\begin{align*} 3 \cdot \textcolor{#c34632}{y} + 4\cdot \textcolor{#c34632}{y}+6 &=20 &&\text{(Identify like terms.)}\\ \boxed{3 \cdot \textcolor{#c34632}{y}} + \boxed{4\cdot \textcolor{#c34632}{y}}+6 &=20 \\ (3+4) \cdot \textcolor{#c34632}{y} +6 &=20 && \text{(Apply a \textcolor{#4257b2}{distributive property.})} \\ 7 \cdot \textcolor{#c34632}{y} +6 &=20 && \text{(Add within the parentheses.)}\\ 7 \cdot \textcolor{#c34632}{y} +6-\textcolor{#4257b2}{6} &=20- \textcolor{#4257b2}{6} && \text{(Subtract \textcolor{#4257b2}{6} to both sides.)}\\ 7 \cdot \textcolor{#c34632}{y} &=14 && \text{(Divide by 7.)} \\ \frac{7 \cdot \textcolor{#c34632}{y}}{7} &= \frac{14}{7} \\ \frac{\cancel7 \cdot \textcolor{#c34632}{y}}{\cancel7} &= \frac{14}{7} \\ \textcolor{#c34632}{y} &= \boxed{2} \end{align*}

## Recommended textbook solutions #### Go Math: Middle School, Grade 7

1st EditionISBN: 9780544056756Holt McDougal
3,175 solutions #### Mathematics Grade 8 (Common Core Edition)

1st EditionISBN: 9780547647197Holt McDougal
2,956 solutions #### Saxon Math, Course 2

1st EditionISBN: 9781591418351Hake, Stephen
4,848 solutions #### Saxon Math, Course 3

1st EditionISBN: 9781591418849Hake
4,042 solutions