Question

A rancher wants to build a fence for a square lot with dimensions of 50 yd by 50 yd. He wants to install a fence post every 5 yd with a post at each corner. How many fence posts will he need?

Solution

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If the side of the square lot is s=50s=50 yd, then the perimeter of the lot is P=4s=4(50)=200P=4s=4(50)=200. If the rancher places a post every 5 yd, then he needs 2005=40\dfrac{200}{5}=40 posts.

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